MATH SOLVE

3 months ago

Q:
# The width of a rectangular park is 23.4 yards. What is the perimeter of the park if the length is 2.5 times larger than the width.

Accepted Solution

A:

Answer:163.8 ydStep-by-step explanation:The perimeter of a rectangle is twice the length added to twice the width.The width is 23.4 yd.The length is 2.5 times the width, so to find the length, we multiply the width by 2.5.length = 2.5 * width = 2.5 * 23.4 yd = 58.5 ydThe length is 58.5 yd.perimeter = 2 * length + 2 * widthperimeter = 2 * 58.5 yd + 2 * 23.4 ydperimeter = 117 yd + 46.8 ydperimeter = 163.8 yd